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BIN_DEC_HEX(1)			    rrdtool			BIN_DEC_HEX(1)

NAME
       bin_dec_hex - How to use	binary,	decimal, and hexadecimal notation.

DESCRIPTION
       Most people use the decimal numbering system. This system uses ten sym-
       bols  to	 represent  numbers.  When those ten symbols are used up, they
       start all over again and	increment the position to the left. The	 digit
       0  is  only shown if it is the only symbol in the sequence, or if it is
       not the first one.

       If this sounds cryptic to you, this is what I've	just said in numbers:

	    0
	    1
	    2
	    3
	    4
	    5
	    6
	    7
	    8
	    9
	   10
	   11
	   12
	   13

       and so on.

       Each time the digit nine	is incremented,	it is reset to 0 and the posi-
       tion before (to the left) is incremented	(from 0	to 1). Then  number  9
       can  be	seen as	"00009"	and when we should increment 9,	we reset it to
       zero and	increment the digit just before	the 9 so  the  number  becomes
       "00010".	 Leading  zeros	 we don't write	except if it is	the only digit
       (number 0). And of course, we write zeros if they occur anywhere	inside
       or at the end of	a number:

	"00010"	-> " 0010" -> "	010" ->	"  10",	but not	"  1 ".

       This was	pretty basic, you already knew this. Why did I tell it?	 Well,
       computers usually do not	represent numbers with	10  different  digits.
       They only use two different symbols, namely "0" and "1".	Apply the same
       rules to	this set of digits and you get the binary numbering system:

	    0
	    1
	   10
	   11
	  100
	  101
	  110
	  111
	 1000
	 1001
	 1010
	 1011
	 1100
	 1101

       and so on.

       If  you	count  the  number of rows, you'll see that these are again 14
       different numbers. The numbers are the same and mean the	same as	in the
       first list, we just used	a different representation.  This  means  that
       you  have  to know the representation used, or as it is called the num-
       bering system or	base.  Normally, if we do not explicitly  specify  the
       numbering system	used, we implicitly use	the decimal system. If we want
       to use any other	numbering system, we'll	have to	make that clear. There
       are  a few widely adopted methods to do so. One common form is to write
       1010(2) which means that	you wrote down a number	in its	binary	repre-
       sentation. It is	the number ten.	If you would write 1010	without	speci-
       fying the base, the number is interpreted as one	thousand and ten using
       base 10.

       In  books,  another  form is common. It uses subscripts (little charac-
       ters, more or less in between two rows).	You can	leave out  the	paren-
       theses in that case and write down the number in	normal characters fol-
       lowed by	a little two just behind it.

       As  the	numbering  system used is also called the base,	we talk	of the
       number 1100 base	2, the number 12 base 10.

       Within the binary system, it is common to write leading zeros. The num-
       bers are	written	down in	series of four,	eight or sixteen depending  on
       the context.

       We  can	use  the  binary  form	when talking to	computers (...program-
       ming...), but the numbers will have large representations.  The	number
       65'535  (often  in the decimal system a ' is used to separate blocks of
       three   digits	for   readability)   would   be	  written   down    as
       1111111111111111(2)  which  is 16 times the digit 1.  This is difficult
       and prone to errors. Therefore, we  usually  would  use	another	 base,
       called  hexadecimal.  It	 uses  16 different symbols. First the symbols
       from the	decimal	system are used, thereafter we	continue  with	alpha-
       betic  characters.  We  get 0, 1, 2, 3, 4, 5, 6,	7, 8, 9, A, B, C, D, E
       and F. This system is chosen because the	hexadecimal form can  be  con-
       verted into the binary system very easily (and back).

       There  is  yet another system in	use, called the	octal system. This was
       more common in the old days, but	is not used very often anymore.	As you
       might find it in	use sometimes, you should get used  to	it  and	 we'll
       show  it	 below.	It's the same story as with the	other representations,
       but with	eight different	symbols.

	Binary	    (2)
	Octal	    (8)
	Decimal	    (10)
	Hexadecimal (16)

	(2)    (8) (10)	(16)
	00000	0    0	  0
	00001	1    1	  1
	00010	2    2	  2
	00011	3    3	  3
	00100	4    4	  4
	00101	5    5	  5
	00110	6    6	  6
	00111	7    7	  7
	01000  10    8	  8
	01001  11    9	  9
	01010  12   10	  A
	01011  13   11	  B
	01100  14   12	  C
	01101  15   13	  D
	01110  16   14	  E
	01111  17   15	  F
	10000  20   16	 10
	10001  21   17	 11
	10010  22   18	 12
	10011  23   19	 13
	10100  24   20	 14
	10101  25   21	 15

       Most computers used nowadays are	using bytes of eight bits. This	 means
       that  they store	eight bits at a	time. You can see why the octal	system
       is not the most practical for that: You'd need three digits  to	repre-
       sent  the eight bits and	this means that	you'd have to use one complete
       digit to	represent only two bits	(2+3+3=8). This	is a waste. For	 hexa-
       decimal digits, you need	only two digits	which are used completely:

	(2)	 (8)  (10) (16)
	11111111 377  255   FF

       You  can	 see  why binary and hexadecimal can be	converted quickly: For
       each hexadecimal	digit there are	exactly	four binary  digits.   Take  a
       binary  number:	take four digits from the right	and make a hexadecimal
       digit from it (see the table above). Repeat this	 until	there  are  no
       more  digits.  And the other way	around:	Take a hexadecimal number. For
       each digit, write down its binary equivalent.

       Computers (or rather the	parsers	running	on them)  would	 have  a  hard
       time  converting	 a number like 1234(16). Therefore hexadecimal numbers
       are specified with a prefix. This prefix	depends	on the language	you're
       writing in. Some	of the prefixes	are "0x" for C,	"$"  for  Pascal,  "#"
       for  HTML.  It is common	to assume that if a number starts with a zero,
       it is octal. It does not	matter what is used as long as you  know  what
       it  is. I will use "0x" for hexadecimal,	"%" for	binary and "0" for oc-
       tal.  The following numbers are all the same, just  their  represenata-
       tion (base) is different: 021 0x11 17 %00010001

       To  do  arithmetics  and	 conversions  you  need	to understand one more
       thing.  It is something you already know	but perhaps you	do  not	 "see"
       it yet:

       If  you	write down 1234, (no prefix, so	it is decimal) you are talking
       about the number	one thousand, two hundred and thirty four. In sort  of
       a formula:

	1 * 1000 = 1000
	2 *  100 =  200
	3 *   10 =   30
	4 *    1 =    4

       This can	also be	written	as:

	1 * 10^3
	2 * 10^2
	3 * 10^1
	4 * 10^0

       where ^ means "to the power of".

       We  are	using  the base	10, and	the positions 0,1,2 and	3.  The	right-
       most position should NOT	be multiplied with 10.	The  second  from  the
       right  should  be multiplied one	time with 10. The third	from the right
       is multiplied with 10 two times.	This continues for whatever  positions
       are used.

       It is the same in all other representations:

       0x1234 will be

	1 * 16^3
	2 * 16^2
	3 * 16^1
	4 * 16^0

       01234 would be

	1 * 8^3
	2 * 8^2
	3 * 8^1
	4 * 8^0

       This  example  can  not be done for binary as that system only uses two
       symbols.	Another	example:

       %1010 would be

	1 * 2^3
	0 * 2^2
	1 * 2^1
	0 * 2^0

       It would	have been easier to convert it to  its	hexadecimal  form  and
       just  translate	%1010  into 0xA. After a while you get used to it. You
       will not	need to	do any calculations anymore, but just  know  that  0xA
       means 10.

       To  convert  a decimal number into a hexadecimal	you could use the next
       method. It will take some time to be able to do the estimates,  but  it
       will  be	 easier	when you use the system	more frequently. We'll look at
       yet another way afterwards.

       First you need to know how many positions will be  used	in  the	 other
       system. To do so, you need to know the maximum numbers you'll be	using.
       Well,  that's  not  as hard as it looks.	In decimal, the	maximum	number
       that you	can form with two digits  is  "99".  The  maximum  for	three:
       "999".  The next	number would need an extra position. Reverse this idea
       and you will see	that the number	can be found by	taking 10^3  (10*10*10
       is 1000)	minus 1	or 10^2	minus one.

       This can	be done	for hexadecimal	as well:

	16^4 = 0x10000 = 65536
	16^3 =	0x1000 =  4096
	16^2 =	 0x100 =   256
	16^1 =	  0x10 =    16

       If  a  number is	smaller	than 65'536 it will fit	in four	positions.  If
       the number is bigger than 4'095,	you must use  position	4.   How  many
       times  you  can subtract	4'096 from the number without going below zero
       is the first digit you write down. This will always be a	number from  1
       to 15 (0x1 to 0xF). Do the same for the other positions.

       Let's  try with 41'029. It is smaller than 16^4 but bigger than 16^3-1.
       This means that we have to use four positions.  We  can	subtract  16^3
       from  41'029  ten  times	without	going below zero.  The left-most digit
       will therefore be "A", so we have 0xA????.  The number  is  reduced  to
       41'029  -  10*4'096  = 41'029-40'960 = 69.  69 is smaller than 16^3 but
       not bigger than 16^2-1. The second digit	is therefore "0"  and  we  now
       have  0xA0??.   69  is smaller than 16^2	and bigger than	16^1-1.	We can
       subtract	16^1 (which is just plain 16) four times and write down	"4" to
       get 0xA04?.  Subtract 64	from 69	(69 - 4*16) and	the last  digit	 is  5
       --> 0xA045.

       The  other method builds	ub the number from the right. Let's try	41'029
       again.  Divide by 16 and	do not use fractions (only whole numbers).

	41'029 / 16 is 2'564 with a remainder of 5. Write down 5.
	2'564 /	16 is 160 with a remainder of 4. Write the 4 before the	5.
	160 / 16 is 10 with no remainder. Prepend 45 with 0.
	10 / 16	is below one. End here and prepend 0xA.	End up with 0xA045.

       Which method to use is up to you. Use whatever works for	 you.	I  use
       them both without being able to tell what method	I use in each case, it
       just  depends  on the number, I think. Fact is, some numbers will occur
       frequently while	programming. If	the number is close to one I am	famil-
       iar with, then I	will use the first method (like	32'770 which  is  into
       32'768 +	2 and I	just know that it is 0x8000 + 0x2 = 0x8002).

       For binary the same approach can	be used. The base is 2 and not 16, and
       the  number of positions	will grow rapidly. Using the second method has
       the advantage that you can see very easily if you should	write  down  a
       zero or a one: if you divide by two the remainder will be zero if it is
       an even number and one if it is an odd number:

	41029 /	2 = 20514 remainder 1
	20514 /	2 = 10257 remainder 0
	10257 /	2 =  5128 remainder 1
	 5128 /	2 =  2564 remainder 0
	 2564 /	2 =  1282 remainder 0
	 1282 /	2 =   641 remainder 0
	  641 /	2 =   320 remainder 1
	  320 /	2 =   160 remainder 0
	  160 /	2 =    80 remainder 0
	   80 /	2 =    40 remainder 0
	   40 /	2 =    20 remainder 0
	   20 /	2 =    10 remainder 0
	   10 /	2 =	5 remainder 0
	    5 /	2 =	2 remainder 1
	    2 /	2 =	1 remainder 0
	    1 /	2 below	0 remainder 1

       Write down the results from right to left: %1010000001000101

       Group by	four:

	%1010000001000101
	%101000000100 0101
	%10100000 0100 0101
	%1010 0000 0100	0101

       Convert into hexadecimal: 0xA045

       Group %1010000001000101 by three	and convert into octal:

	%1010000001000101
	%1010000001000 101
	%1010000001 000	101
	%1010000 001 000 101
	%1010 000 001 000 101
	%1 010 000 001 000 101
	%001 010 000 001 000 101
	   1   2   0   1   0   5 --> 0120105

	So: %1010000001000101 =	0120105	= 0xA045 = 41029
	Or: 1010000001000101(2)	= 120105(8) = A045(16) = 41029(10)
	Or: 1010000001000101(2)	= 120105(8) = A045(16) = 41029

       At  first  while	 adding	 numbers, you'll convert them to their decimal
       form and	then back into their original form after doing	the  addition.
       If  you	use the	other numbering	system often, you will see that	you'll
       be able to do arithmetics directly in the base that is  used.   In  any
       representation it is the	same, add the numbers on the right, write down
       the right-most digit from the result, remember the other	digits and use
       them  in	 the next round. Continue with the second digit	from the right
       and so on:

	   %1010 + %0111 --> 10	+ 7 -->	17 --> %00010001

       will become

	   %1010
	   %0111 +
	    ||||
	    |||+-- add 0 + 1, result is	1, nothing to remember
	    ||+--- add 1 + 1, result is	%10, write down	0 and remember 1
	    |+---- add 0 + 1 + 1(remembered), result = 0, remember 1
	    +----- add 1 + 0 + 1(remembered), result = 0, remember 1
		   nothing to add, 1 remembered, result	= 1
	--------
	  %10001 is the	result,	I like to write	it as %00010001

       For low values, try to do the calculations yourself,  then  check  them
       with  a calculator. The more you	do the calculations yourself, the more
       you'll find that	you didn't make	mistakes. In the end, you'll  do  cal-
       culi in other bases as easily as	you do them in decimal.

       When  the numbers get bigger, you'll have to realize that a computer is
       not called a computer just to have a nice name. There are many  differ-
       ent  calculators	available, use them. For Unix you could	use "bc" which
       is short	for Binary Calculator. It calculates not only in decimal,  but
       in all bases you'll ever	want to	use (among them	Binary).

       For  people  on	Windows: Start the calculator (start->programs->acces-
       sories->calculator) and if necessary click  view->scientific.  You  now
       have a scientific calculator and	can compute in binary or hexadecimal.

AUTHOR
       I hope you enjoyed the examples and their descriptions. If you do, help
       other people by pointing	them to	this document when they	are asking ba-
       sic  questions.	They  will  not	only get their answer, but at the same
       time learn a whole lot more.

       Alex van	den Bogaerdt  <alex@ergens.op.het.net>

1.2.30				  2009-01-19			BIN_DEC_HEX(1)

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