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std::deque::pop_front(3) C++ Standard Libary std::deque::pop_front(3) NAME std::deque::pop_front - std::deque::pop_front Synopsis void pop_front(); Removes the first element of the container. If there are no elements in the container, the behavior is undefined. Iterators and references to the erased element are invalidated. It is unspecified whether the past-the-end iterator is invalidated if the (until C++11) element is the last element in the container. Other references and iterators are not affected. Iterators and references to the erased element are invalidated. If the element is the last element in the container, the past-the-end (since C++11) iterator is also invalidated. Other references and iterators are not affected. Parameters (none) Return value (none) Complexity Constant. Exceptions Does not throw. Example // Run this code #include <deque> #include <iostream> int main() { std::deque<char> chars{'A', 'B', 'C', 'D'}; for (; !chars.empty(); chars.pop_front()) { std::cout << "chars.front(): '" << chars.front() << "'\n"; } } Output: chars.front(): 'A' chars.front(): 'B' chars.front(): 'C' chars.front(): 'D' See also pop_back removes the last element (public member function) push_front inserts an element to the beginning (public member function) front access the first element (public member function) http://cppreference.com 2022.07.31 std::deque::pop_front(3)
NAME | Synopsis | Parameters | Return value | Complexity | Exceptions | Example | Output: | See also
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