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std::filesy...ot_directory(3) C++ Standard Libarystd::filesy...ot_directory(3) NAME std::filesystem::path::root_directory - std::filesystem::path::root_di- rectory Synopsis path root_directory() const; (since C++17) Returns the root directory of the generic-format path. If the path (in generic format) does not include root directory, returns path(). Parameters (none) Return value The root directory of the path. Exceptions May throw implementation-defined exceptions. Example // Run this code #include <iostream> #include <filesystem> namespace fs = std::filesystem; int main() { fs::path p = fs::current_path(); std::cout << "The current path " << p << " decomposes into:\n" << "root name " << p.root_name() << '\n' << "root directory " << p.root_directory() << '\n' << "relative path " << p.relative_path() << '\n'; } Possible output: The current path "C:\Users\abcdef\Local Settings\temp" decomposes into: root name "C:" root directory "\" relative path "Users\abcdef\Local Settings\temp" See also root_name returns the root-name of the path, if present (public member function) root_path returns the root path of the path, if present (public member function) http://cppreference.com 2022.07.31 std::filesy...ot_directory(3)
NAME | Synopsis | Parameters | Return value | Exceptions | Example | Possible output: | See also
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