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std::partition_point(3) C++ Standard Libary std::partition_point(3) NAME std::partition_point - std::partition_point Synopsis Defined in header <algorithm> template< class ForwardIt, class UnaryPredicate > (since C++11) ForwardIt partition_point( ForwardIt first, ForwardIt last, (until C++20) UnaryPredicate p ); template< class ForwardIt, class UnaryPredicate > constexpr ForwardIt partition_point( ForwardIt first, ForwardIt last, (since C++20) UnaryPredicate p ); Examines the partitioned (as if by std::partition) range [first, last) and locates the end of the first partition, that is, the first element that does not satisfy p or last if all elements satisfy p. Parameters first, last - the partitioned range of elements to examine unary predicate which returns true for the elements found in the beginning of the range. The expression p(v) must be convertible to bool for every argument v p - of type (possibly const) VT, where VT is the value type of ForwardIt, regardless of value category, and must not modify v. Thus, a parameter type of VT&is not allowed , nor is VT unless for VT a move is equivalent to a copy (since C++11). Type requirements - ForwardIt must meet the requirements of LegacyForwardIterator. - UnaryPredicate must meet the requirements of Predicate. Return value The iterator past the end of the first partition within [first, last) or last if all elements satisfy p. Complexity Given N = std::distance(first, last), performs O(log N) applications of the predicate p. However, for non-LegacyRandomAccessIterators, the number of iterator increments is O(N). Notes This algorithm is a more general form of std::lower_bound, which can be expressed in terms of std::partition_point with the predicate [&](auto const& e) { return e < value; });. Example // Run this code #include <algorithm> #include <array> #include <iostream> #include <iterator> auto print_seq = [](auto rem, auto first, auto last) { for (std::cout << rem; first != last; std::cout << *first++ << ' ') {} std::cout << '\n'; }; int main() { std::array v = { 1, 2, 3, 4, 5, 6, 7, 8, 9 }; auto is_even = [](int i){ return i % 2 == 0; }; std::partition(v.begin(), v.end(), is_even); print_seq("After partitioning, v: ", v.cbegin(), v.cend()); const auto pp = std::partition_point(v.cbegin(), v.cend(), is_even); const auto i = std::distance(v.cbegin(), pp); std::cout << "Partition point is at " << i << "; v[" << i << "] = " << *pp << '\n'; print_seq("First partition (all even elements): ", v.cbegin(), pp); print_seq("Second partition (all odd elements): ", pp, v.cend()); } Possible output: After partitioning, v: 8 2 6 4 5 3 7 1 9 Partition point is at 4; v[4] = 5 First partition (all even elements): 8 2 6 4 Second partition (all odd elements): 5 3 7 1 9 See also find find_if finds the first element satisfying specific criteria find_if_not (function template) (C++11) is_sorted checks whether a range is sorted into as- cending order (C++11) (function template) returns an iterator to the first element not less than the lower_bound given value (function template) ranges::partition_point locates the partition point of a partitioned range (C++20) (niebloid) http://cppreference.com 2022.07.31 std::partition_point(3)
NAME | Synopsis | Parameters | Type requirements | Return value | Complexity | Notes | Example | Possible output: | See also
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