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std::ranges::fill(3) C++ Standard Libary std::ranges::fill(3) NAME std::ranges::fill - std::ranges::fill Synopsis Defined in header <algorithm> Call signature template< class T, std::output_iterator<const T&> O, std::sentinel_for<O> S > (1) (since C++20) constexpr O fill( O first, S last, const T& value ); template< class T, ranges::output_range<const T&> R > constexpr ranges::borrowed_iterator_t<R> fill( R&& r, const T& (2) (since C++20) value ); 1) Assigns the given value to the elements in the range [first, last). 2) Same as (1), but uses r as the source range, as if using ranges::begin(r) as first and ranges::end(r) as last. The function-like entities described on this page are niebloids, that is: * Explicit template argument lists may not be specified when call- ing any of them. * None of them is visible to argument-dependent lookup. * When one of them is found by normal unqualified lookup for the name to the left of the function-call operator, it inhibits argument-dependent lookup. In practice, they may be implemented as function objects, or with special compiler extensions. Parameters first, last - the range of elements to modify r - the range of elements to modify value - the value to be assigned Return value An output iterator that compares equal to last. Complexity Exactly last - first assignments. Possible implementation struct fill_fn { template< class T, std::output_iterator<const T&> O, std::sen- tinel_for<O> S > constexpr O operator()( O first, S last, const T& value ) const { while (first != last) { *first++ = value; } return first; } template< class T, ranges::output_range<const T&> R > constexpr ranges::borrowed_iterator_t<R> operator()( R&& r, const T& value ) const { return (*this)(ranges::begin(r), ranges::end(r), value); } }; inline constexpr fill_fn fill; Example The following code uses ranges::fill() to set all of the elements of a vector of ints first to -1, then to 10. // Run this code #include <algorithm> #include <vector> #include <iostream> int main() { std::vector<int> v{0, 1, 2, 3, 4, 5, 6, 7, 8, 9}; namespace ranges = std::ranges; ranges::fill(v.begin(), v.end(), -1); for (auto elem : v) { std::cout << elem << " "; } std::cout << "\n"; ranges::fill(v, 10); for (auto elem : v) { std::cout << elem << " "; } std::cout << "\n"; } Output: -1 -1 -1 -1 -1 -1 -1 -1 -1 -1 10 10 10 10 10 10 10 10 10 10 See also ranges::fill_n assigns a value to a number of elements (C++20) (niebloid) ranges::copy ranges::copy_if copies a range of elements to a new location (C++20) (niebloid) (C++20) ranges::generate saves the result of a function in a range (C++20) (niebloid) ranges::transform applies a function to a range of elements (C++20) (niebloid) fill copy-assigns the given value to every element in a range (function template) http://cppreference.com 2022.07.31 std::ranges::fill(3)
NAME | Synopsis | Parameters | Return value | Complexity | Possible implementation | Example | Output: | See also
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