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std::ranges...erator::base(3) C++ Standard Libarystd::ranges...erator::base(3) NAME std::ranges::transform_view::iterator::base - std::ranges::trans- form_view::iterator::base Synopsis constexpr const ranges::iterator_t<Base>& base() const & noexcept; (1) (since C++20) constexpr ranges::iterator_t<Base> base() &&; (2) (since C++20) Returns the underlying iterator. 1) Returns a reference to the underlying iterator. 2) Move constructs the result from the underlying iterator. Parameters (none) Return value 1) A reference to the underlying iterator. 2) An iterator move constructed from the underlying iterator. Example // Run this code #include <algorithm> #include <iostream> #include <iterator> #include <ranges> int main() { const auto v = { 0, 1, 2, 3, 4 }; auto x2 = [](int x) { return x << 1; }; std::ranges::transform_view tv{ v, x2 }; std::ostream_iterator<int> ostr{ std::cout, " " }; std::ranges::copy(v, ostr), std::cout << '\n'; std::ranges::copy(tv.base(), ostr), std::cout << '\n'; std::ranges::copy(tv, ostr), std::cout << '\n'; } Output: 0 1 2 3 4 0 1 2 3 4 0 2 4 6 8 Defect reports The following behavior-changing defect reports were applied retroac- tively to previously published C++ standards. DR Applied to Behavior as published Correct behavior LWG 3533 C++20 the const& overload of base returns a copy re- turns a reference of the underlying iterator LWG 3593 C++20 the const& overload of base might not be made noexcept noexcept http://cppreference.com 2022.07.31 std::ranges...erator::base(3)
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