std::common_with(3) C++ Standard Libary std::common_with(3) NAME std::common_with - std::common_with Synopsis Defined in header <concepts> template< class T, class U > concept common_with = std::same_as<std::common_type_t<T, U>, std::common_type_t<U, T>> && requires { static_cast<std::common_type_t<T, U>>(std::declval<T>()); static_cast<std::common_type_t<T, U>>(std::declval<U>()); } && (since C++20) std::common_reference_with< std::add_lvalue_reference_t<const T>, std::add_lvalue_reference_t<const U>> && std::common_reference_with< std::add_lvalue_reference_t<std::common_type_t<T, U>>, std::common_reference_t< std::add_lvalue_reference_t<const T>, std::add_lvalue_reference_t<const U>>>; The concept common_with<T, U> specifies that two types T and U share a common type (as computed by std::common_type_t) to which both can be converted. Semantic requirements T and U model std::common_with<T, U> only if, given equality-preserving expressions t1, t2, u1 and u2 such that decltype((t1)) and decltype((t2)) are both T and decltype((u1)) and decltype((u2)) are both U, * std::common_type_t<T, U>(t1) equals std::common_type_t<T, U>(t2) if and only if t1 equals t2; and * std::common_type_t<T, U>(u1) equals std::common_type_t<T, U>(u2) if and only if u1 equals u2. In other words, the conversion to the common type must preserve equal- ity. Equality preservation Expressions declared in requires expressions of the standard library concepts are required to be equality-preserving (except where stated otherwise). See also common_type determines the common type of a group of types (C++11) (class template) common_reference determines the common reference type of a group of types basic_common_reference (class template) (C++20) common_reference_with specifies that two types share a common reference type (C++20) (concept) http://cppreference.com 2024.06.10 std::common_with(3)
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