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std::common_with(3) C++ Standard Libary std::common_with(3) NAME std::common_with - std::common_with Synopsis Defined in header <concepts> template< class T, class U > concept common_with = std::same_as<std::common_type_t<T, U>, std::common_type_t<U, T>> && requires { static_cast<std::common_type_t<T, U>>(std::declval<T>()); static_cast<std::common_type_t<T, U>>(std::declval<U>()); } && (since C++20) std::common_reference_with< std::add_lvalue_reference_t<const T>, std::add_lvalue_reference_t<const U>> && std::common_reference_with< std::add_lvalue_reference_t<std::common_type_t<T, U>>, std::common_reference_t< std::add_lvalue_reference_t<const T>, std::add_lvalue_reference_t<const U>>>; The concept common_with<T, U> specifies that two types T and U share a common type (as computed by std::common_type_t) to which both can be converted. Semantic requirements T and U model std::common_with<T, U> only if, given equality-pre- serving expressions t1, t2, u1 and u2 such that decltype((t1)) and decltype((t2)) are both T and decltype((u1)) and decltype((u2)) are both U, * std::common_type_t<T, U>(t1) equals std::common_type_t<T, U>(t2) if and only if t1 equals t2; and * std::common_type_t<T, U>(u1) equals std::common_type_t<T, U>(u2) if and only if u1 equals u2. In other words, the conversion to the common type must preserve equality. Equality preservation Expressions declared in requires expressions of the standard library concepts are required to be equality-preserving (except where stated otherwise). See also common_type determines the common type of a group of types (C++11) (class template) common_reference determines the common reference type of a group of types basic_common_reference (class template) (C++20) common_reference_with specifies that two types share a common ref- erence type (C++20) (concept) http://cppreference.com 2024.06.10 std::common_with(3)
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