std::numeri...mits::lowest(3) C++ Standard Libary std::numeri...mits::lowest(3) NAME std::numeric_limits::lowest - std::numeric_limits::lowest Synopsis static constexpr T lowest() noexcept; (since C++11) Returns the lowest finite value representable by the numeric type T, that is, a finite value x such that there is no other finite value y where y < x. This is different from std::numeric_limits<T>::min() for floating-point types. Only meaningful for bounded types. Return value T std::numeric_limits<T>::lowest() /* non-specialized */ T() bool false char CHAR_MIN signed char SCHAR_MIN unsigned char 0 wchar_t WCHAR_MIN char8_t (since C++20) 0 char16_t 0 char32_t 0 short SHRT_MIN unsigned short 0 int INT_MIN unsigned int 0 long LONG_MIN unsigned long 0 long long LLONG_MIN unsigned long long 0 float -FLT_MAX double -DBL_MAX long double -LDBL_MAX Notes For every standard C++ floating-point type T std::numeric_lim- its<T>::lowest() == -std::numeric_limits<T>::max(), but this does not necessarily have to be the case for any third-party specialization. Example Demonstrates min(), max(), and lowest() for floating-point types: // Run this code #include <iostream> #include <limits> #include <string_view> template<typename T> void print_twice(std::string_view type, T value) { std::cout << '\t' << type << ": " << std::defaultfloat << value << " or " << std::hexfloat << value << '\n'; } int main() { // min() std::cout << "std::numeric_limits<T>::min():\n"; print_twice("float", std::numeric_limits<float>::min()); print_twice("double", std::numeric_limits<double>::min()); print_twice("long double", std::numeric_limits<long double>::min()); // lowest() std::cout << "std::numeric_limits<T>::lowest():\n"; print_twice("float", std::numeric_limits<float>::lowest()); print_twice("double", std::numeric_limits<double>::lowest()); print_twice("long double", std::numeric_limits<long double>::low- est()); // max() std::cout << "std::numeric_limits<T>::max():\n"; print_twice("float", std::numeric_limits<float>::max()); print_twice("double", std::numeric_limits<double>::max()); print_twice("long double", std::numeric_limits<long double>::max()); } Output: std::numeric_limits<T>::min(): float: 1.17549e-38 or 0x1p-126 double: 2.22507e-308 or 0x1p-1022 long double: 3.3621e-4932 or 0x8p-16385 std::numeric_limits<T>::lowest(): float: -3.40282e+38 or -0x1.fffffep+127 double: -1.79769e+308 or -0x1.fffffffffffffp+1023 long double: -1.18973e+4932 or -0xf.fffffffffffffffp+16380 std::numeric_limits<T>::max(): float: 3.40282e+38 or 0x1.fffffep+127 double: 1.79769e+308 or 0x1.fffffffffffffp+1023 long double: 1.18973e+4932 or 0xf.fffffffffffffffp+16380 See also min returns the smallest finite value of the given type [static] (public static member function) denorm_min returns the smallest positive subnormal value of the given floating-point [static] type (public static member function) max returns the largest finite value of the given type [static] (public static member function) http://cppreference.com 2024.06.10 std::numeri...mits::lowest(3)
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