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std::chrono...i_clock::now(3) C++ Standard Libarystd::chrono...i_clock::now(3) NAME std::chrono::tai_clock::now - std::chrono::tai_clock::now Synopsis static std::chrono::time_point<std::chrono::tai_clock> now(); (since C++20) Returns a time point representing the current point in time. The re- sult is calculated as if by std::chrono::tai_clock::from_utc(std::chrono::utc_clock::now()). Implementations may use a more accurate value of TAI time. Parameters (none) Return value A time point representing the current time. Example // Run this code #include <iostream> #include <iomanip> #include <vector> #include <numeric> #include <chrono> volatile int sink; int main() { std::cout << std::fixed << std::setprecision(9) << std::left; for (auto size = 1ull; size < 1000'000'000ull; size *= 100) { // record start time auto start = std::chrono::tai_clock::now(); // do some work std::vector<int> v(size, 42); sink = std::accumulate(v.begin(), v.end(), 0u); // make sure it's a side effect // record end time auto end = std::chrono::tai_clock::now(); std::chrono::duration<double> diff = end - start; std::cout << "Time to fill and iterate a vector of " << std::setw(9) << size << " ints : " << diff.count() << " s\n"; } } Possible output: Time to fill and iterate a vector of 1 ints : 0.000006568 s Time to fill and iterate a vector of 100 ints : 0.000002854 s Time to fill and iterate a vector of 10000 ints : 0.000116290 s Time to fill and iterate a vector of 1000000 ints : 0.011742752 s Time to fill and iterate a vector of 100000000 ints : 0.505534949 s http://cppreference.com 2022.07.31 std::chrono...i_clock::now(3)
NAME | Synopsis | Parameters | Return value | Example | Possible output:
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