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std::chrono...weekday_last(3) C++ Standard Libarystd::chrono...weekday_last(3) NAME std::chrono::weekday_last::weekday_last - std::chrono::week- day_last::weekday_last Synopsis explicit constexpr weekday_last( const std::chrono::weekday& wd ) (since C++20) noexcept; Constructs a weekday_last object storing the weekday wd. Notes A more convenient way to construct a weekday_last is with weekday's operator[], i.e., wd[std::chrono::last]. Example // Run this code #include <chrono> #include <iostream> using namespace std::chrono; int main() { const year_month_day ymd { floor<days>(system_clock::now()) }; const weekday_last wdl { Sunday[last] }; // A last Sunday of a month const year_month_day last_sun { ymd.year() / ymd.month() / wdl }; std::cout << "The last Sunday of current month falls on " << (int)last_sun.year() << '/' << (unsigned)last_sun.month() << '/' << (unsigned)last_sun.day() << '\n'; } Possible output: The last Sunday of current month falls on 2021/9/26 http://cppreference.com 2022.07.31 std::chrono...weekday_last(3)
NAME | Synopsis | Notes | Example | Possible output:
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