std::chrono::year::is_leap(3) C++ Standard Libary std::chrono::year::is_leap(3) NAME std::chrono::year::is_leap - std::chrono::year::is_leap Synopsis constexpr bool is_leap() const noexcept; (since C++20) Determines if *this represents a leap year in the proleptic Gregorian calendar. *this represents a leap year if the stored year value * is divisible by 4 and not divisible by 100; or * is divisible by 400. Return value true if *this represents a leap year, otherwise false. Example // Run this code #include <chrono> #include <iostream> int main() { using namespace std::chrono_literals; for (const std::chrono::year y : {2020y, 2021y, 2000y, 3000y}) { if (const int iy{static_cast<int>(y)}; y.is_leap()) std::cout << iy << " is a leap year because it is divisible by " << (iy % 400 == 0 ? "400\n" : "4 and not divisible by 100\n"); else std::cout << iy << " is not a leap year\n"; } } Output: 2020 is a leap year because it is divisible by 4 and not divisible by 100 2021 is not a leap year 2000 is a leap year because it is divisible by 400 3000 is not a leap year http://cppreference.com 2024.06.10 std::chrono::year::is_leap(3)
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