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std::chrono::year::year(3)     C++ Standard Libary    std::chrono::year::year(3)

NAME
     std::chrono::year::year - std::chrono::year::year

Synopsis
	year() = default;			   (1) (since C++20)
	constexpr explicit year( int y ) noexcept; (2) (since C++20)

	Constructs a year object.

	1) Default constructor leaves the year value uninitialized.
	2)  If y is in the range [-32767, 32767], constructs a year object hold-
     ing the year
	value y. Otherwise the value held is unspecified.

Example
     // Run this code

      #include <chrono>
      #include <iostream>

      int main()
      {
	  using namespace std::chrono;

	  constexpr int leap_years = []
	  {
	      int count{};
	      for (int i{year::min()}; i <= int{year::max()}; ++i)
		  if (year{i}.is_leap()) // uses constructor (2)
		      ++count;
	      return count;
	  } ();

	  static_assert(15891 == leap_years);

	  std::cout << "There are " << leap_years << " leap years in  the  range
     ["
		    << int(year::min()) << ", " << int(year::max()) << "].\n";
      }

Output:
      There are 15891 leap years in the range [-32767, 32767].

http://cppreference.com 	   2024.06.10	      std::chrono::year::year(3)
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