home | help
std::filesy...ot_directory(3)  C++ Standard Libary std::filesy...ot_directory(3)

NAME
     std::filesystem::path::root_directory  - std::filesystem::path::root_direc-
     tory

Synopsis
	path root_directory() const;  (since C++17)

	Returns the root directory of the generic-format path. If the  path  (in
     generic
	format) does not include root directory, returns path().

Parameters
	(none)

Return value
	The root directory of the path.

Exceptions
	May throw implementation-defined exceptions.

Example
     // Run this code

      #include <filesystem>
      #include <iostream>
      namespace fs = std::filesystem;

      int main()
      {
	  fs::path p = fs::current_path();

	  std::cout << "The current path " << p << " decomposes into:\n"
		    << "root name " << p.root_name() << '\n'
		    << "root directory " << p.root_directory() << '\n'
		    << "relative path " << p.relative_path() << '\n';
      }

Possible output:
      The current path "C:\Users\abcdef\Local Settings\temp" decomposes into:
      root name "C:"
      root directory "\"
      relative path "Users\abcdef\Local Settings\temp"

See also
	root_name returns the root-name of the path, if present
		  (public member function)
	root_path returns the root path of the path, if present
		  (public member function)

http://cppreference.com 	   2024.06.10	   std::filesy...ot_directory(3)

home | help