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std::ranges::next(3) C++ Standard Libary std::ranges::next(3) NAME std::ranges::next - std::ranges::next Synopsis Defined in header <iterator> Call signature template< std::input_or_output_iterator I > (1) (since C++20) constexpr I next( I i ); template< std::input_or_output_iterator I > (2) (since C++20) constexpr I next( I i, std::iter_difference_t<I> n ); template< std::input_or_output_iterator I, std::sentinel_for<I> S > (3) (since C++20) constexpr I next( I i, S bound ); template< std::input_or_output_iterator I, std::sentinel_for<I> S > (4) (since C++20) constexpr I next( I i, std::iter_difference_t<I> n, S bound ); Return the nth successor of iterator i. The function-like entities described on this page are niebloids, that is: * Explicit template argument lists may not be specified when call- ing any of them. * None of them is visible to argument-dependent lookup. * When one of them is found by normal unqualified lookup for the name to the left of the function-call operator, it inhibits argument-dependent lookup. In practice, they may be implemented as function objects, or with special compiler extensions. Parameters i - an iterator n - number of elements to advance bound - sentinel denoting the end of the range i points to Return value 1) The successor of iterator i 2) The nth successor of iterator i 3) The first iterator equivalent to bound 4) The nth successor of iterator i, or the first iterator equivalent to bound, whichever is first. Complexity 1) Constant. 2) Constant if I models std::random_access_iterator; otherwise lin- ear. 3) Constant if I and S models both std::random_access_iterator<I> and std::sized_sentinel_for<S, I>, or if I and S models std::assigna- ble_from<I&, S>; otherwise linear. 4) Constant if I and S models both std::random_access_iterator<I> and std::sized_sentinel_for<S, I>; otherwise linear. Possible implementation struct next_fn { template<std::input_or_output_iterator I> constexpr I operator()(I i) const { ++i; return i; } template<std::input_or_output_iterator I> constexpr I operator()(I i, std::iter_difference_t<I> n) const { ranges::advance(i, n); return i; } template<std::input_or_output_iterator I, std::sentinel_for<I> S> constexpr I operator()(I i, S bound) const { ranges::advance(i, bound); return i; } template<std::input_or_output_iterator I, std::sentinel_for<I> S> constexpr I operator()(I i, std::iter_difference_t<I> n, S bound) const { ranges::advance(i, n, bound); return i; } }; inline constexpr auto next = next_fn(); Notes Although the expression ++x.begin() often compiles, it is not guar- anteed to do so: x.begin() is an rvalue expression, and there is no requirement that specifies that increment of an rvalue is guaranteed to work. In particular, when iterators are implemented as pointers or its operator++ is lvalue-ref-qualified, ++x.begin() does not compile, while ranges::next(x.begin()) does. Example // Run this code #include <iomanip> #include <iostream> #include <iterator> #include <vector> int main() { std::cout << std::boolalpha; std::vector<int> v{ 3, 1, 4 }; { auto n = std::ranges::next(v.begin()); std::cout << *n << '\n'; } { auto n = std::ranges::next(v.begin(), 2); std::cout << *n << '\n'; } { auto n = std::ranges::next(v.begin(), v.end()); std::cout << (n == v.end()) << '\n'; } { auto n = std::ranges::next(v.begin(), 42, v.end()); std::cout << (n == v.end()) << '\n'; } } Output: 1 4 true true See also ranges::prev decrement an iterator by a given distance or to a bound (C++20) (niebloid) ranges::advance advances an iterator by given distance or to a given bound (C++20) (niebloid) next increment an iterator (C++11) (function template) http://cppreference.com 2022.07.31 std::ranges::next(3)
NAME | Synopsis | Parameters | Return value | Complexity | Possible implementation | Notes | Example | Output: | See also
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