std::ratio_add(3) C++ Standard Libary std::ratio_add(3) NAME std::ratio_add - std::ratio_add Synopsis Defined in header <ratio> template< class R1, class R2 > (since C++11) using ratio_add = /* see below */; The alias template std::ratio_add denotes the result of adding two exact rational fractions represented by the std::ratio specializations R1 and R2. The result is a std::ratio specialization std::ratio<U, V>, such that given Num == R1::num * R2::den + R2::num * R1::den and Denom == R1::den * R2::den (computed without arithmetic overflow), U is std::ratio<Num, Denom>::num and V is std::ratio<Num, Denom>::den. Notes If U or V is not representable in std::intmax_t, the program is ill- formed. If Num or Denom is not representable in std::intmax_t, the program is ill- formed unless the implementation yields correct values for U and V. The above definition requires that the result of std::ratio_add<R1, R2> be already reduced to lowest terms; for example, std::ratio_add<std::ratio<1, 3>, std::ratio<1, 6>> is the same type as std::ratio<1, 2>. Example // Run this code #include <iostream> #include <ratio> int main() { using two_third = std::ratio<2, 3>; using one_sixth = std::ratio<1, 6>; using sum = std::ratio_add<two_third, one_sixth>; std::cout << "2/3 + 1/6 = " << sum::num << '/' << sum::den << '\n'; } Output: 2/3 + 1/6 = 5/6 See also ratio_subtract subtracts two ratio objects at compile-time (C++11) (alias template) http://cppreference.com 2024.06.10 std::ratio_add(3)
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